Judging from the
sizes of Keno lounges, the casino game of Keno is not as popular with
casino players as it once was. Still many people play the game and many,
many more are now playing it in connection with state lotteries. In
my own state (Massachusetts) one can play Keno at selected bar rooms
every four minutes from 5:00 PM until the bar closes. For those few
of you who might not know how it is played let me explain the rules;
I'll use the six spot game to illustrate them.
The player selects six numbers from the numbers 1 through 80 and marks
them on a special Keno card. The player then takes the card to a lottery
representative (a Keno runner, an official in the Keno lounge, or, in
the case of state lotteries, a lottery representative located in the
bar). The numbers are entered into the computer and the player receives
a receipt confirming his number selection.
The Keno game then
randomly selects 20 of the numbers 1 through 80 and displays them on
an eight by ten grid. In casinos this selection is made using a ping
pong ball blower similar to that used in Bingo games and in lottery
games the selection is made using a random number generator.
If enough of the
player's numbers match the 20 selected by the Keno game then the player
wins a cash prize. Here is the payout schedule for the Massachusetts
6 spot Keno game:
Number of Matches
Payoff
6
1600
5
50
4
7
3
1
0 through 2
0
Figure 1
Typical Keno Payout
Is
this a good deal? Let's find out using some of the ideas we learned
in last month's article.
It will be convenient to imagine that the Keno game is played a bit
differently than it really is. I want to suppose that the 20 Keno numbers
are picked prior to the player's 6 picks but the player doesn't know
what they are until they are displayed on the Keno board. Clearly this
is equivalent to the game as it is actually played.
Very well, once the 20 Keno numbers are selected the 80 numbers are
partitioned into two sets, the twenty that I'll dub winners and the
remaining 60 that I'll dub losers. If we want to know how many ways
there are to pick six numbers that consist of, say four winners and
two losers, this would just be the number of ways to pick four out of
twenty times the number of ways to pick two out of sixty. Using our
results from last month's article, this would simply be C(20,4) x C(60,2).
Using the formula we derived for C(n,k) this is just
C(20,4)
x C(60,2) = 4,845 x 1,770 = 8,575,650
The
other outcomes are calculated in an analogous manner. The results are
tabulated below
Symbols
Calculation
Result
C(20,6) x C(60,2)
38,760 x 1
38,760
C(20,5)
x C(60,1)
15,504
x 60
930,240
C(20,4) x C(60,2)
4,845 x 1,770
8,575,650
C(20,3) x C(60,3)
1,140 x 34,220
39,010,800
C(20,2) x C(60,4)
190 x 487,635
92,650,650
C(20,1) x C(60,5)
20 x 5,461,512
109,230,240
C(20,0) x C(20,6)
1 x 50,063,860
50,063,860
Total -
---
207,568,350
Figure
2
Keno Calculations
Observe
that the total number of ways to pick six numbers out of 80 is just
C(80,6) and if you calculate that number it is 300,500,200, exactly
the same as the total in Figure 2. This is a good way to check that
our calculations are correct. Here is another interesting fact. From
5:00 PM to 1:00 AM (closing time) there are 120 four-minute intervals.
If you divide the total number of combinations by 120 and then divide
the result by 365, it turns out that you alone would have to play Keno
for approximately 6,861 years to play every six number combination.
We
are now in a position to analyze Keno. Suppose that 300,500,200 people
bet a dollar each, each person having a different six-number combination
from any of the other players. Clearly the Keno operator (casino or
lottery) would collect $300,500,200. How much of this would be returned
to the players. From figures 1 and 2 we can construct the table shown
in Figure 3. Here is the explanation of how the table is formed. 38,760
of the players will match six numbers and each then gets $1600 back.
So, the total returned in this case would be the product of 38,760 times
$1600 which is $62,016,000. The same type of calculation holds for each
of the other matches. The figures under the Product column, therefore,
represent monies returned to the players. The sum, which is shown in
the lower right corner, represents the total returned to the players.
Matches
Frequency
Payback
Product
6
38,760
1600
62,016,000
5
930,240
50
46,512,000
4
8,575,65
7
60,029,550
3
39,010,800
1
39,010,800
2
92,650,650
0
0
1
109,230,240
0
0
0
50,063,860
0
0
Total-
300,500,200
---
207,568,350
Figure 3
Total Return Calculation
The
difference between the money wagered and the amount returned is the
amount that is kept by the Keno operator; that figure is $92,931,850.
This represents approximately 30.926% of the amount wagered and is the
house edge on this game. It is huge! Clearly the Massachusetts Keno
game is one to avoid. What about other Keno games?
Suffice
it to say that some are better than others but they are all bad. In
his January 2005 edition of the Las Vegas Advisor, Anthony Curtis quotes
Charles Lund as reporting that the El Cortez in downtown Las Vegas offers
a Keno game that returns 85.9% to the players. This is the highest return
I've heard of, but it is still poor.
Although
I used the six-spot game to illustrate the Keno calculation, any Keno
game can be analyzed using the ideas above. The payouts are obtained
from a Keno brochure and the frequencies can be calculated as I did
in Figure 2. Here is a tip though. For games with a lot of spots you
will run into some huge numbers. If you want to see how to keep the
numbers manageable just write to me at 711cat@comcast.net and I'll give
you the details.
About
the Author
Don
Catlin is a Professor of Mathematics and Statistics at the University
of Massachusetts in Amherst. In addition to his research in stochastic
estimation applied to submarine navigation problems, he has been
both a casino gambler and a fascinated observer of casino gambling.
In his business Technigame (P.O. Box 9427, North Amherst, MA 01059-9427),
Don does mathematical analyses for gaming developers. magazine among
others.
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